Calculus: Early Transcendentals 9th Edition

Published by Cengage Learning
ISBN 10: 1337613924
ISBN 13: 978-1-33761-392-7

Chapter 1 - Review - True-False Quiz - Page 67: 6

Answer

False

Work Step by Step

if g(x) = 2x and f(x) = $x^2$ f(g(x)) = $(2x)^2$ g(f(x)) = $2(x^2)$ $2x^2\ne 4x^2$ therefore $f(g(x)) \ne g(f(x))$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.