Answer
$y=\frac{2}{3}x-\frac{1}{3}$
Work Step by Step
First, we find the slope as follows
$$
m=\frac{y_2-y_1}{x_2-x_1}=\frac{1-5}{2-8}=\frac{4}{6}=\frac{2}{3}
.$$
The point-slope form of a line is given as:
$$y-y_1=m(x-x_1)$$
We plug in the given point and slope and solve for $y$:
$$y-1=\frac{2}{3}(x-2)\Longrightarrow y=\frac{2}{3}x-\frac{4}{3}+1=\frac{2}{3}x-\frac{1}{3}
.$$
