Answer
neither
Work Step by Step
$x-4y=12$
$x-4y-x=12-x$
$-4y\div-4=(-x+12)\div-4$
$y=\underset\uparrow{\frac{1}{4}}x-3$
$\ \ \ \ \ \ $slope
$x+4y=16$
$x+4y-x=16-x$
$4y\div4=(-x+16)\div4$
$y=-\underset\uparrow{\frac{1}{4}}x+4$
$\ \ \ \ \ \ \ \ $slope
The slopes are not equal and are not negative inverse, so are not parallel or perpendicular.
