Answer
(3,1)
(0,3)
(-3,5)
Work Step by Step
$2x+3y=9$
$2x+3y-2x=9-2x$
$3y=9-2x$
$3y\div3=(9-2x)\div3$
$y=3-\frac{2}{3}x$
if $x=3$
$y=3-\frac{2}{3}(3)=3-2=1$
if $x=0$
$y=3-\frac{2}{3}(0)=3-0=3$
if $x=-3$
$y=3-\frac{2}{3}(-3)=3-(-2)=3+2=5$