Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 8 - Cumulative Review - Page 318: 3

Answer

$$a=4\frac{3}{16} \ in.$$ $$b=2\frac{7}{8} \ in.$$

Work Step by Step

According to the figure, we have $$a=3\frac{1}{2}+4\frac{1}{8}+3\frac{1}{2}-6\frac{15}{16}\\ =\frac{7}{2}+\frac{33}{8}+\frac{7}{2}-\frac{111}{16}\\ =\frac{112}{16}+\frac{66}{16}-\frac{111}{16}=\frac{67}{16} =4\frac{3}{16} \ in.$$ $$b=5\frac{1}{4} -2\frac{3}{8}=\frac{21}{4} - \frac{19}{8}\\ =\frac{42}{8} - \frac{19}{8}=\frac{23}{8} =2\frac{7}{8} \ in.$$
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