Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.4 - Inverse Variation - Exercises - Page 288: 47

Answer

$3\ A$

Work Step by Step

Since the current and resistance vary inversely in a circuit with a given voltage, then for a given voltage, we have (resistance)( amperes)=(resistance)( amperes). Now, we have $$ 30\times 8=80\times x\Longrightarrow x=\frac{30\times 8 }{ 80}=3\ A .$$
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