Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.2 - Proportion - Exercises - Page 278: 86

Answer

$60\;g$.

Work Step by Step

The given values are Base $B=600\;mL$. Rate $R=10$. Let the pure crystalline glucose is $P=x$ The formula is $\Rightarrow \frac{P}{B}=\frac{R}{100}$ Substitute all the values. $\Rightarrow \frac{x}{600\;mL}=\frac{10}{100}$ Cross multiply. $\Rightarrow 100x=6000\;mL$ Divide both sides by $100$. $\Rightarrow x=60\;mL$. Convert $mL$ to $g$. $\Rightarrow x=60\;mL\times \frac{1g}{1mL}$. Simplify. $\Rightarrow x=60\;g$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.