Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 7 - Section 7.2 - Proportion - Exercises - Page 277: 61

Answer

$216\;hp$.

Work Step by Step

Displacement is proportional to the horsepower. Let the required horsepower is $x$. We can write. $\Rightarrow \frac{2.0\;L}{270\;hp}=\frac{1.6\;L}{x}$ Cross multiply. $\Rightarrow 2x=270\times 1.6$ Divide both sides by $2$. $\Rightarrow x=\frac{270\times 1.6}{2}$ Simplify. $\Rightarrow x=216\;hp$.
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