Answer
$0.43\;in.$
Work Step by Step
The given values are
Constant $\alpha =6.5\times10^{-6} /^{\circ}F$
Original length $l=50.0\;ft$.
Change in temperature $\Delta T=110 ^{\circ}F$
The given formula is
$\Delta l=\alpha l \Delta T$
Substitute all the values.
$\Delta l=(6.5\times10^{-6} /^{\circ}F) \times (50.0\;ft) \times (110 ^{\circ}F)$
Simplify.
$\Delta l=0.035750 \;ft$
Convert $ft$ into $inches$.
$\Delta l=35750 \;ft\times \frac{12\;in.}{1\;ft}$
Simplify.
$\Delta l=0.429000\;in.$
Rounded value.
$\Delta l=0.43\;in.$.
