Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Section 6.7 - Formulas - Exercises - Page 256: 27

Answer

$$ C=\frac{5}{9} (F - 32) .$$

Work Step by Step

To solve the given equation for $ C$, we multiply both sides by $\frac{5}{9}$ and then we simplify as follows: $$ F=\frac{9}{5}C+32\Longrightarrow \frac{5}{9} F=C+\frac{5}{9}(32) \Longrightarrow C=\frac{5}{9} F - \frac{5}{9}(32)\\ \Longrightarrow C=\frac{5}{9} (F - 32) .$$
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