Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Review - Page 263: 27

Answer

$$m= \frac{2k}{v^2} $$

Work Step by Step

We multiply both sides by $2$ and then we divide by $v^2$ as follows: $$2k=mv^2 \Longrightarrow \frac{2k}{v^2}= \frac{v^2m}{v^2} \Longrightarrow m= \frac{2k}{v^2} .$$
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