Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 6 - Cumulative Review - Page 264: 7

Answer

$$43.4\ \ ft^2$$

Work Step by Step

Since $1\ in=2.54 \ cm$ and $1\ ft= 30.48 \ cm$, then we have $$6250 \ in^2= 6250\times 2.54^2 \ cm^2=\frac{40322.5 }{30.48^2} \ ft^2\\ =43.4\ \ ft^2.$$
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