Answer
$32.$
Work Step by Step
Since we have $x=4$ and $y=-1$, then:
$$
\frac{3x^2y-4x}{2y}=\frac{3(4)^2(-1)-4(4)}{2(-1)}\\
=\frac{-48-16}{-2}=\frac{-64}{-2}=32.
$$
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