Answer
$-54a^3b^5$
Work Step by Step
Multiply the numerical coefficients. Add the powers of the variables.
$(-9ab^2)(6a^2 b^3)=(-9\times6)a^{1+2}b^{2+3}=-54a^3b^5$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 5 - Section 5.4 - Multiplication of Monomials - Exercise - Page 223: 12
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