Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Section 4.9 - Reading Scales - Exercise - Page 205: 33

Answer

$$12 \ \Omega.$$

Work Step by Step

The needle is on the second graduation to the right of 10. Each subdivision is 1 $\Omega$. Therefore, the reading is $$10 \ \Omega+2\cdot 1 \ \Omega=12 \ \Omega.$$
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