Answer
$$0.80 \ A
.$$
Work Step by Step
Since we have
$$
I_1+I_2+I_3=I_4+I_5
.$$
Then, we get
$$
I_5=I_1+I_2+I_3-I_4\\
=0.45 \ A+0.207 \ A+1.009 \ A-0.87 \ A\\
=0.796 \ A \approx 0.80 A
.$$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 4 - Section 4.5 - Addition and Subtraction of Measurements - Exercise - Page 185: 44
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