Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 4 - Cumulative Review - Page 210: 32

Answer

$0.001~cm$, $0.0005~cm$, $0.00023$, $0.02\%$

Work Step by Step

For the measurement $2.135~cm$, we have: The last digit $5$ is in the $0.001$ place, so the precision is $0.001~cm$. The greatest possible error is one-half the precision: $0.5\cdot 0.001 \ rpm=0.0005 \ cm$ The relative error is $relative~error=\dfrac{greatest~possible~error}{measurement}$ $\frac{0.0005\ cm}{2.135\ cm}=0.00023$ The percent of error is $0.02\%$.
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