Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 3 - Section 3.6 - Temperature - Exercise - Page 152: 14

Answer

$140^oF=60^oC.$

Work Step by Step

To change from degrees Fahrenheit to degrees Celsius, we use the formula $$C=\frac{5}{9}(F-32^o)=\frac{5}{9}(140^o-32^o)=\frac{5}{9}\times 108=60^o$$ that is $140^oF=60^oC.$
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