Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 2 - Review - Page 133: 40

Answer

$$2.03\times 10^{-15}$$

Work Step by Step

By raising each factor to the exponent and multiplying the double exponents, we have $$(4.5\times 10^{-8})^2=20.25\times 10^{-16}=2.03\times 10^{-15}$$ which is in the scientific notation.
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