Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 15 - Section 15.13 - Probability - Exercise - Page 542: 16

Answer

(a) $\frac{2}{5}$ (b) $\frac{3}{5}$ (c) $1$

Work Step by Step

Since the bag contains $6$ red marbles and $4$ white marbles, the total number of marbles in the bag will be $6+4=10$ marbles. (a) The question asks for the probability that a white marble is drawn. There are $4$ white marbles out of $10$ total marbles. We can use the formula for probability here, $P=\frac{n}{s}$. $P=\frac{n}{s}$ $P=\frac{4}{10}$ $P=\frac{2}{5}$ (b) The question asks for the probability that a red marble is drawn. There are $6$ red marbles out of $10$ total marbles. We can use the formula for probability here, $P=\frac{n}{s}$. $P=\frac{n}{s}$ $P=\frac{6}{10}$ $P=\frac{3}{5}$ (c) Sum = $\frac{2}{5}+\frac{3}{5}$ (Add the numerators together) =$\frac{5}{5}$ = $1$
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