Answer
$2.0\times 10^{-4}\;s$.
Work Step by Step
Frequency $f=5.0\;kHz$
$f=5000\; Hz$
The relation between frequency and the period is
$f=\frac{1}{T}$
Isolate $T$.
$T=\frac{1}{f}$
Plug value of $f$.
$T=\frac{1}{5000\;Hz}$
We can write $\frac{1}{Hz}=s$
$T=\frac{1}{5000}s$
$T=0.0002\;s$
$T=2.0\times 10^{-4}\;s$.
