Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 13 - Section 13.5 - Applications Involving Trigonometric Ratios - Exercise - Page 464: 7

Answer

$ 5^{\circ}$

Work Step by Step

In the figure Illustration 5 is a right angle triangle. Let the angle of inclination is $\theta$. One leg is $a=220\;ft$. Second leg is $b=2300\; ft$. By using trigonometric ratios. $\tan{\theta}=\frac{220\;ft}{2300\;ft}$ Isolate $\theta$. $\theta =\tan^{-1}{\left ( \frac{220\;ft}{2300\;ft}\right )}$ Simplify. $\theta = 5^{\circ}$ (rounded value.).
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