Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 13 - Section 13.5 - Applications Involving Trigonometric Ratios - Exercise - Page 463: 5

Answer

$x=32.3\;ft$. $A=58.2^{\circ}$.

Work Step by Step

In the figure Illustration 3 is a right angle triangle. Where, given values are Hypotenuse $c=38.0\;ft$. one leg $a=20.0\;ft$. other leg $b=x$. By using Pythagorean theorem. $c^2=a^2+b^2$ Plug all values. $(38.0\;ft)^2=(20.0\;ft)^2+x^2$ Isolate $x$. $x=\sqrt{(38.0\;ft)^2-(20.0\;ft)^2}$ Simplify. $x=\sqrt{(1444\;ft^2-400\;ft^2}$ $x=\sqrt{(1044\;ft^2}$ $x=32.3\;ft$. By using trigonometric ratios. $\cos{A}=\frac{20.0\;ft}{38.0\;ft}$ Isolate $A$. ${A}=\cos^{-1}\left(\frac{20.0\;ft}{38.0\;ft} \right )$ Simplfiy. $A=58.2^{\circ}$.
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