Answer
$$A=11.8°$$
$$B=78.2°$$
Work Step by Step
Find angle A.
We can use the trigonometric function for sine to find angle A.
$sin A=\frac{a}{c}$
$sin A=\frac{16.7m}{81.4m}$
$sin A=0.2052$
Now we solve for A by multiplying both sides of the equation by the inverse sine.
So,
$sin^{-1}(sin A) = sin^{-1}(0.2052)$
$A = sin^{-1}(0.2052)$
$A=11.8°$
Find angle B.
We know that in right triangles the sum of the acute angles is 90°.
So, $A+B=90°$
Solving for $B$, we get
$B=90°-A$
$B=90°-11.8°$
$B=78.2°$
