Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 13 - Review - Page 470: 19

Answer

$B=58.8^{\circ}$. $b=102 \;m$. $c=119 \;m$.

Work Step by Step

Given values are one leg $a=61.7\;m$. $A=31.2^{\circ}$ In a right angle triangle sum of the other two angles is equal to $90^{\circ}$. $A+B=90^{\circ}$ Isolate $B$. $B=90^{\circ}-A$ Plug value of $A$. $B=90^{\circ}-31.2^{\circ}$ Simplify. $B=58.8^{\circ}$ By using trigonometric ratios. $\frac{a}{c}=\sin{A}$ Isolate $c$. $c=\frac{a}{\sin{A}}$ Plug all values. $c=\frac{61.7}{\sin{(31.2^{\circ})}}$ Simplify. $c=119 \;m$ (rounded value). By using trigonometric ratios. $\frac{a}{b}=\tan{A}$ Isolate $b$. $b=\frac{a}{\tan{A}}$ Plug all values. $b=\frac{61.7\;m}{\tan{(31.2^{\circ})}}$ Simplify. $b=102 \;m$ (rounded value).
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