Answer
$11\bar{0}0\ m^3$
Work Step by Step
The volume of a pyramid is given by
$$
V=\frac{1}{3} Bh=\frac{1}{3}=\frac{1}{3} \times 18.8\times 10.78\times 16.2= 1094.38 \ m^3\approx 11\bar{0}0\ m^3
$$
where $B$ is the area of the base and $h$ is the height of the pyramid.
