Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.9 - Cylinders - Exercise - Page 434: 5

Answer

$69,700\ mm^3$

Work Step by Step

The volume of a pyramid is given by $$ V=\frac{1}{3} Bh=\frac{1}{3} \times \frac{1}{2} \times101\times 115\times 36= 69690\ mm^3\approx 69,700\ mm^3 $$ where $B$ is the area of the base (right triangle with area $\frac{1}{2}bh$) and $h$ is the height of the pyramid.
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