Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.2 - Quadrilaterals - Exercise - Page 393: 45

Answer

$ 105 \ ft$

Work Step by Step

Since the area of a parallelogram is $A=lw$, we have $$ A=lw\Longrightarrow 27,800=265 w\\ \Longrightarrow w=\frac{27,800}{265}=104.905\ ft \approx 105 \ ft .$$
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