Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 12 - Section 12.1 - Angles and Polygons - Exercise - Page 388: 21

Answer

$$\angle 1= \angle3=90^o.$$ $$\angle 2= \angle4=90^o.$$

Work Step by Step

Since $\angle 1, \angle 3$ are suplementray, then $\angle 1+ \angle 3=180$. They are equal since they are vertical angles, so $\angle 1= \angle 3$, and hence $$2\angle 1=180$$ that is $$\angle 1= \angle3=90^o.$$ Similarly, $\angle 2, \angle 4$ are vertical angles and $\angle 3+ \angle 4=360-180=180$, and hence $$2\angle 3=180$$ that is $$\angle 3= \angle4=90^o.$$
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