Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Test - Page 380: 4

Answer

$x=\frac{1}{6}, -\frac{1}{2}$.

Work Step by Step

We solve by factoring as follows: $$ 12x^2+4x-1=0\Longrightarrow (6x-1)(2x+1)=0 $$ that is $6x-1=0$ or $2x+1=0$ and so $x=\frac{1}{6}, -\frac{1}{2}$.
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