Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 11 - Section 11.3 - Applications Involving Quadratic Equations - Exercise - Page 370: 10

Answer

$18$ inches

Work Step by Step

We have a square aluminum sheet, which means each side will be of equal length. After the small $4$-inch squares are cut out from each corner, the sheet is folded up. This means that a cuboid shape has formed, not a cube, as the height of the shape is different from the length and width. We know that the formula for the volume of a cuboid is Length $\times$ Width $\times$ Height We also know that: Volume of shape = $400$ $in^3$ Length = $x$ Width = $x$ Height = $4$ (The height is 4 inches as the sides are each $4$ inches tall when folded) So, we can substitute these values into the formula to find a quadratic equation! Volume = Length $\times$ Width $\times$ Height $400 = x \times x \times 4$ $400 = 4x^2$ In this case, we can simply divide each side by 4 and then square root both sides to find the solutions for $x$. $x^2=\frac{400}{4}$ $x^2=100$ $x= \sqrt {100}$ $x= ±10$ (As we are square rooting, the answer can either be negative or positive, hence the ± sign) However, in this case, we can discard the negative solution as we are looking for the dimensions of an aluminum sheet, which cannot be below 0. The original size can be given by the expression $(x+8)$ inches. Original size =$(10)+8$ $=18$ inches
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.