Answer
$0.6 + 0.663j,\ or, \ 0.6 - 0.663j$
Work Step by Step
For the equation $5x^2 -6x+4 = 0$, we use the quadratic formula as follows
$$ x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}, \\
a=5, \quad b=-6, \quad c=4
.$$ That is,
$$ x=\frac{6 \pm \sqrt{36-80}}{2(5) }=0.6 + 0.663j,\ or, \ 0.6 - 0.663j
.$$
