Answer
$3(x-2)(x+1)$
Work Step by Step
For the polynomial
$$
3x^2-3x-6=3(x^2-x-2)
$$
Finding the factors of $-2$, we have $-2$ and $1$ ($-2+1=-1$ and $-2\times 1=-2$)
$$
3(x^2-x-2)=3(x-2)(x+1)
.$$
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