Answer
$3abc(abc+9a^2b^2c-27)$
Work Step by Step
3abc is a common factor.
$3a^2b^2c^2+27a^3b^3c^2-81abc=3abc(abc+9a^2b^2c-27)$
Elementary Technical Mathematics
by Nelson, Robert; Eren, Dale;
Published by
Brooks Cole
ISBN 10:
1285199197
ISBN 13:
978-1-28519-919-1
Chapter 10 - Section 10.1 - Finding Monomial Factors - Exercise - Page 345: 41
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
