Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Review - Page 358: 40

Answer

$(5y-10)(5y+10)=25(y+2)(y-2)$

Work Step by Step

Factoring the difference of two squares, we have $$ 25y^2-100=(5y-10)(5y+10) .$$ This can be further factored as: $$(5y-10)(5y+10)=5(y-2)5(y+2)=25(y+2)(y-2)$$
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