Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 10 - Cumulative Review - Page 358: 5

Answer

$0.625 \ kg$

Work Step by Step

Since $1 kg= 1000 g$, we have $$ 625\ g =\frac{625}{1000} \ kg=0.625 \ kg .$$
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