Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Unit 1B Review - Page 54: 5

Answer

$1\frac{1}{2}$

Work Step by Step

Make the fractions similar using their LCD of $6$ to obtain: $=\frac{5}{6} + \frac{2(2)}{3(2)} \\=\frac{5}{6}+\frac{4}{6} \\=\frac{5+4}{6} \\=\frac{9}{6} \\=1\frac{3}{6} \\=1\frac{1}{2}$
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