Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Test - Page 103: 29

Answer

$10\frac{11}{16}\ A$

Work Step by Step

In a parallel circuit the total current is the sum of each leg. Convert each fraction to the least common denominator and add the numerators. $3\frac{5}{8}\ A+2\frac{3}{4}\ A+4\frac{5}{16}\ A=3\frac{5\times2}{8\times2}\ A+2\frac{3\times4}{4\times4}\ A+4\frac{5}{16}\ A=3\frac{10}{16}\ A+2\frac{12}{16}\ A+4\frac{5}{16}\ A=9\frac{27}{16}\ A=10\frac{11}{16}\ A$
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