Elementary Technical Mathematics

Published by Brooks Cole
ISBN 10: 1285199197
ISBN 13: 978-1-28519-919-1

Chapter 1 - Section 1.9 - The U.S. System of Weights and Measures - Exercises - Page 53: 28

Answer

960 rod

Work Step by Step

$3\ mi\times\frac{5280\ ft}{1\ mi}\times\frac{1\ rod}{16.5\ ft}=15840\ ft\times\frac{1\ rod}{16.5\ ft}=960\ rod$
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