Answer
2 $\frac{2}{3}$ $ft^{3}$
Work Step by Step
A concrete pad for mounting a condensing unit is of length 4ft, width is 2$\frac{2}{3}$ ft and thickness = $\frac{1}{4}$ ft
Volume = lwh
= 4 ft x 2$\frac{2}{3}$ ft x $\frac{1}{4}$ ft
= 4 x $\frac{8}{3}$ x $\frac{1}{4}$
= $\frac{8}{3}$
=2 $\frac{2}{3}$ $ft^{3}$
