Answer
$\$4983.73$.
Work Step by Step
Let the money owed $=A$.
The given values are
Time $t=4\;years$.
Borrowed $P=\$4000$.
Rate of interest $r=5.5\%=0.055$.
Number of periods $n=52$.
Formula $A=P(1+\frac{r}{n})^{nt}$.
Substitute all values into the formula.
$A=4000(1+\frac{0.055}{52})^{52\cdot 4}$.
Simplify.
$A=4000(1+0.0010576923)^{ 208}$
$A=4000(1.0010576923)^{ 208}$
$A=4983.73$.
