Answer
$I_{total}= 2.605 A$
Work Step by Step
The total current in the parallel circuit is the addition of every branch current in the circuit.
So,
$I_{total} = 0.3 A + 0.105 A + 0.45 A + 0.93 A + 0.27 A + 0.55 A$
$I_{total}= 2.605 A$
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