Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - 1.1 Exercises - Page 10: 9

Answer

The solution set is (4,8,5,2).

Work Step by Step

Starting from the original matrix: 1 -1 0 0 -4 0 1 -3 0 -7 0 0 1 -3 -1 0 0 0 2 4 We do the following operations: Divide the last row by 2 1 -1 0 0 -4 0 1 -3 0 -7 0 0 1 -3 -1 0 0 0 1 2 add 3 times the 4th row to the 3rd row 1 -1 0 0 -4 0 1 -3 0 -7 0 0 1 0 5 0 0 0 1 2 add 3 times the 3rd row to the 2nd row 1 -1 0 0 -4 0 1 0 0 8 0 0 1 0 5 0 0 0 1 2 add the 2nd row to the 1st row 1 0 0 0 4 0 1 0 0 8 0 0 1 0 5 0 0 0 1 2 And the solution set is the last entries of each row, in order.
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