Answer
{$-2,-1,2$}
Work Step by Step
Given: $x^3+x^2=4x+4$
Solve the given expression as follows:
$x^3+x^2-4x-4=0$
or, $x^2(x+1)-4(x+1)=0$
or, $(x+1)(x^2-4)=0$
or, $(x+1)(x-2)(x+2)=0$
or, $x=-1,-2,2$
Our solution set is: {$-2,-1,2$}