Answer
$20$%
Work Step by Step
Since, $A=(1+r)^t$
Plug the values in the given expression.
Such as $A=(1+r)^t$
or, $2880=2000(1+r)^2$
This implies that $r=\sqrt {\dfrac{2880}{2000}}-1$
or, $r=0.2$ and
Hence, $r$ can be written as: $r\approx 20$%
