Answer
$\frac{9}{4}$
Work Step by Step
$x^2 - 3x$
The coefficient of the x-term in $x^2 - 3x$ is $-3$. Half of $-3$ is $-\frac{3}{2}$, and $(-\frac{3}{2})^2 = \frac{9}{4}$
Add $\frac{9}{4}$.
The result is a perfect square trinomial.
$x^2 - 3x + \frac{9}{4} = (x -\frac{3}{2})^2$