Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 7 - Section 7.7 - Complex Numbers - Exercise Set - Page 572: 148

Answer

$x=3$ or $x=-3$.

Work Step by Step

$x^2=9\\x^2-9=0\\x^2+3x-3x-9=0\\x(x+3)-3(x+3)\\(x+3)(x-3)=0$ Thus $x=3$ or $x=-3$.
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