Answer
$x=3$ or $x=0$
Work Step by Step
Square both sides of the equation to obtain:
$5x+1=(x+1)^2$
Use the rule $(a+b)^2 = a62 + 2ab+b^2$ where $a=x$ and $b=1$ to obtain:
$\\5x+1=x^2+2x+1$
Move all terms to the right side of the equation. Note that when a term is moved to the other side of the equation, its sign changes to its opposite.
$0=x^2+2x+1-5x-1
\\0=x^2-3x$
Factor the binomial to obtain:
$0=x(x-3)$
Equate each factor to zero then solve each equation to obtain:
$x = 0 \text{ or } x -3 = 0
\\x = 0 \text{ or } x = 3$
