Answer
$\sqrt[3]{18} + 7\sqrt[3]{12}$
Work Step by Step
RECALL:
(1) Distributive Property:
For any real numbers a, b, and c,
$a(b+c)=ab+ac$
(2) For any real numbers real numbers a and b within the domain,
$\sqrt[n]{a} \cdot \sqrt[n]{b}=\sqrt[n]{ab}$
Use rule (1) above to obtain:
$=\sqrt[3]{3}(\sqrt[3]{6}) + \sqrt[3]{3} \cdot 7\sqrt[3]{4}$
Use rule (2) above to obtain:
$=\sqrt[3]{3(6)} + 7\sqrt[3]{3(4)}
\\=\sqrt[3]{18} + 7\sqrt[3]{12}$
