Answer
$(x+3)(x-3)(y-3)$
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
Hence here: $x^2y-9y-3x^2+27=y(x^2-9)-3(x^2-9)=(x^2-3^2)(y-3)=(x+3)(x-3)(y-3)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 6 - Section 6.8 - Modeling Using Variation - Exercise Set - Page 491: 61
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